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If $${x^2} + \frac{1}{{{x^2}}} = 38,$$ then what is the value of $$\left( {x - \frac{1}{x}} \right)?$$
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {x^2} + \frac{1}{{{x^2}}} = 38 \cr
& {x^2} + \frac{1}{{{x^2}}} - 2 = 38 - 2 \cr
& {\left( {x - \frac{1}{x}} \right)^2} = 36 \cr
& x - \frac{1}{x} = 6 \cr} $$
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