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If $$x = \root 3 \of {{x^2} + 11} - 2{\text{,}}$$ then the value of x3 + 5x2 + 12x is?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& x = \root 3 \of {{x^2} + 11} - 2 \cr
& \Rightarrow x + 2 = \root 3 \of {{x^2} + 11} \cr
& \Rightarrow {\text{Taking cube on both side}} \cr
& \Rightarrow {\left( {x + 2} \right)^3} = {x^2} + 11 \cr
& \Rightarrow {x^3} + 8 + 6x\left( {x + 2} \right) = {x^2} + 11 \cr
& \Rightarrow {x^3} + 8 + 6{x^2} + 12x = {x^2} + 11 \cr
& \Rightarrow {x^3} + 5{x^2} + 12x = 3 \cr} $$
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