If x varies inversely as (y2 - 1) and x is equal to 24 when y = 10, then the value of x when y = 5 is?
A. 99
B. 12
C. 24
D. 100
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & x \propto \frac{1}{{{y^2} - 1}}{\text{ }}\left( {{\text{Given}}} \right) \cr & x = k \times \frac{1}{{{y^2} - 1}}\left( {k{\text{ is constant}}} \right) \cr & {\text{Now }}x = 24{\text{ when }}y = 10{\text{ given}} \cr & \Rightarrow 24 = k \times \frac{1}{{{{\left( {10} \right)}^2} - 1}} \cr & \Rightarrow 24 = \frac{k}{{99}} \cr & \Rightarrow k = 24 \times 99 \cr & x = ? \cr & y = 5 \cr & \Rightarrow x = 24 \times 99 \times \frac{1}{{25 - 1}} \cr & \Rightarrow x = 24 \times 99 \times \frac{1}{{24}} \cr & \Rightarrow x = 99 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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