If x = y = 333 and z = 334, then the value of x3 + y3 + z3 - 3xyz is?
A. 0
B. 667
C. 1000
D. 2334
Answer: Option C
Solution(By Examveda Team)
x = y = 333, z = 334⇒ x3 + y3 + z3 - 3xyz = $$\frac{1}{2}$$ (x + y + z) [(x - y)2 + (y - z)2 + (z - x)2]
⇒ x3 + y3 + z3 - 3xyz = $$\frac{1}{2}$$ (333 + 333 + 334) (333 - 333)2 + (333 - 334)2 + (334 - 333)2
⇒ x3 + y3 + z3 - 3xyz = $$\frac{1}{2}$$ (1000) (0 + 1 + 1)
⇒ x3 + y3 + z3 - 3xyz = 1000
This Question Belongs to Arithmetic Ability >> Algebra
Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion