If x, y and z are real numbers such that (x - 3)2 + (y - 4)2 + (z - 5)2 = 0, then (x + y + z) is equal to?
A. 10
B. 14
C. 11
D. 12
Answer: Option D
Solution(By Examveda Team)
This is possible only when$$\eqalign{ & {\left( {x - 3} \right)^2} = 0 \cr & x = 3 \cr & {\left( {y - 4} \right)^2} = 0 \cr & y = 4 \cr & {\left( {z - 5} \right)^2} = 0 \cr & z = 5 \cr & {\text{Then, }}\left( {x + y + z} \right) \cr & = 3 + 4 + 5 \cr & = 12 \cr} $$
Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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