If x + y + z = 0, then the value of (x² + y² + z²) ÷ (z² - xy) is:

Solution (By Examveda Team)

$$\eqalign{ & x + y + z = 0 \cr & {\text{Let }}x = y = 1 \cr & z = - 2 \cr & \frac{{{x^2} + {y^2} + {z^2}}}{{{z^2} - xy}} \cr & = \frac{{1 + 1 + 4}}{{4 - 1}} \cr & = 2 \cr} $$