If x + y + z = 0, then the value of (x2 + y2 + z2) ÷ (z2 - xy) is:
A. 1
B. 2
C. -2
D. -1
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & x + y + z = 0 \cr & {\text{Let }}x = y = 1 \cr & z = - 2 \cr & \frac{{{x^2} + {y^2} + {z^2}}}{{{z^2} - xy}} \cr & = \frac{{1 + 1 + 4}}{{4 - 1}} \cr & = 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion