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If x + y + z = 0, then the value of (x2 + y2 + z2) ÷ (z2 - xy) is:
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& x + y + z = 0 \cr
& {\text{Let }}x = y = 1 \cr
& z = - 2 \cr
& \frac{{{x^2} + {y^2} + {z^2}}}{{{z^2} - xy}} \cr
& = \frac{{1 + 1 + 4}}{{4 - 1}} \cr
& = 2 \cr} $$
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