If (x + y + z) = 0, then what is the value of $$\frac{{3{y^2} + {x^2} + {z^2}}}{{2{y^2} - xz}}?$$
A. 2
B. 1
C. $$\frac{3}{2}$$
D. $$\frac{5}{3}$$
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & x + y + z = 0,\,\frac{{3{y^2} + {x^2} + {z^2}}}{{2{y^2} - xz}} = ? \cr & {\text{Put }}x = 1,\,y = 1,\,z = - 2 \cr & \Rightarrow \frac{{3{{\left( y \right)}^2} + {x^2} + {z^2}}}{{2{y^2} - xz}} \cr & \Rightarrow \frac{{3{{\left( 1 \right)}^2} + {{\left( 1 \right)}^2} + {{\left( { - 2} \right)}^2}}}{{2{{\left( 1 \right)}^2} - \left( {1 \times \left( { - 2} \right)} \right)}} \cr & \Rightarrow \frac{{4 + 4}}{{2 + 2}} \cr & \Rightarrow \frac{8}{4} \cr & \Rightarrow 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion