If x + y + z = 0, then what is the value of $$\frac{{xy + yz + zx}}{{{x^2} + {y^2} + {z^2}}}?$$
A. 1
B. -1
C. $$\frac{1}{2}$$
D. $$ - \frac{1}{2}$$
Answer: Option D
Solution (By Examveda Team)
Given, x + y + z = 0By putting values x = 2, y = -1, z = -1
$$\eqalign{ & {\text{Now, }}\frac{{xy + yz + zx}}{{{x^2} + {y^2} + {z^2}}} \cr & = \frac{{ - 2 + 1 - 2}}{{4 + 1 + 1}} \cr & = \frac{{ - 1}}{2} \cr} $$
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