If x2 - 4x + 1 = 0, then what is the value of x9 + x7 - 194x5 - 194x3?
A. 4
B. -4
C. 1
D. -1
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {x^2} - 4x + 1 = 0 \cr & x + \frac{1}{x} = 4 \cr & {x^2} + \frac{1}{{{x^2}}} = 14 \cr & {x^4} + \frac{1}{{{x^4}}} = 194 \cr & {x^9} + {x^7} - 194{x^5} - 194{x^3} \cr & {x^9} + {x^7} - \left( {{x^4} + \frac{1}{{{x^4}}}} \right){x^5} - \left( {{x^4} + \frac{1}{{{x^4}}}} \right){x^3} \cr & = {x^9} + {x^7} - {x^9} - x - {x^7} - \frac{1}{x} \cr & = - \left( {x + \frac{1}{x}} \right) \cr & = - 4 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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