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If x8 - 1442x4 + 1 = 0, then a possible value of $$x - \frac{1}{x}$$ is:
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {x^8} - 1442{x^4} + 1 = 0 \cr
& \frac{{{x^8}}}{{{x^4}}} - \frac{{1442{x^4}}}{{{x^4}}} + \frac{1}{{{x^4}}} = 0 \cr
& {x^4} - 1442 + \frac{1}{{{x^4}}} = 0 \cr
& {x^4} + \frac{1}{{{x^4}}} = 1442 \cr
& {x^4} + \frac{1}{{{x^4}}} + 2 = 1444 \cr
& \left( {{x^2} + \frac{1}{{{x^2}}}} \right) = 38 \cr
& {x^2} + \frac{1}{{{x^2}}} - 2 = 36 \cr
& {\left( {x - \frac{1}{x}} \right)^2} = 36 \cr
& x - \frac{1}{x} = 6 \cr} $$
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