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If xy = -6 and x3 + y3 = 19 (x and y are integers), then what is the value of $$\frac{1}{{{x^{ - 1}}}} + \frac{1}{{{y^{ - 1}}}}?$$
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& xy = - 6,\,{x^3} + {y^3} = 19 \cr
& {\text{putting }}x = 3,\,y = - 2 \cr
& {\text{both condition are satisfied}} \cr
& {\text{So, }}\frac{1}{{{x^{ - 1}}}} + \frac{1}{{{y^{ - 1}}}} \cr
& = x + y \cr
& = 3 - 2 \cr
& = 1 \cr} $$
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