If $$y = \frac{{2 - x}}{{1 + x}},$$ then what is the value of $$\frac{1}{{y + 1}} + \frac{{2y + 1}}{{{y^2} - 1}}?$$
A. $$\frac{{\left( {1 + x} \right)\left( {2 - x} \right)}}{{2x - 1}}$$
B. $$\frac{{\left( {1 - x} \right)\left( {2 + x} \right)}}{{x - 1}}$$
C. $$\frac{{\left( {1 + x} \right)\left( {2 - x} \right)}}{{1 - 2x}}$$
D. $$\frac{{\left( {1 + x} \right)\left( {2 - x} \right)}}{{1 - x}}$$
Answer: Option C
Related Questions on Surds and Indices
A. $$\frac{1}{2}$$
B. 1
C. 2
D. $$\frac{7}{2}$$
Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to:
A. 1.45
B. 1.88
C. 2.9
D. 3.7
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