If $${y^4} + \frac{1}{{{y^4}}} = 223$$ and y > 1, then find the value of $${y^2} + \frac{1}{{{y^2}}}?$$
A. 15
B. 14
C. 14.86
D. 16
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {y^4} + \frac{1}{{{y^4}}} = 223 \cr & \Rightarrow {y^2} + \frac{1}{{{y^2}}} = \sqrt {223 + 2} \cr & \Rightarrow {y^2} + \frac{1}{{{y^2}}} = \sqrt {225} \cr & \Rightarrow {y^2} + \frac{1}{{{y^2}}} = 15 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion