In a 50% reaction turbine stage, tangential component of absolute velocity at rotor inlet is 537 m/s and the blade velocity is 454 m/s. The power output in kW of steam will be
A. 260 kW
B. 282 kW
C. 296 kW
D. 302 kW
Answer: Option B
This Question Belongs to Mechanical Engineering >> Steam Boilers, Engines, Nozzles And Turbines
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Kgm is the force exerted by earth to pull the mass m
So we have to multipy kgm with acceleration due to garvity to get joule
1kgm = 1kgm×9.81m/sec²=9.81kgm×m/sec2= 9.81joule
Kgm/sec2=newton
I don't really get it, where that 434 come from
50% reaction turbine there is one formula,
Work done = Vb (2V1cos alpha-vb)/(1000).
Substitute and we can get it 454/1000(2*537-434) = 282.