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In a circle with centre O, AB is a diameter and CD is a chord which is equal to the radius OC. AC and BD are extended in such a way that they intersect each other at a point P, exterior to the circle. The measure of ∠APB is
Answer & Solution
Correct Answer:
Option
C
∵ OC = CD = radius
According to property of circle
Same arc angle
Make line AD
Angle BDA = 90° because of semicircle property
∠P = 90° - 30° = 60°
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