In a circle with centre O, BC is a chord. Point D and A are on the circle, on the opposite side of BC, such that ∠DBC = 28° and BD = DC. What is the measure of ∠BOC?
A. 98°
B. 84°
C. 112°
D. 96°
Answer: Option C
Solution (By Examveda Team)
∠DBC = 28° (Given)
BD = DC, (Given)
∠BCD = 28°
So, ∠BDC = 180° - (28° + 28°) = 124°
∠BAC = 180° - 124° = 56°
(Cyclic $$\square $$)
∠BOC = 2 × ∠BAC = 56° × 2 = 112° Answer.
This Question Belongs to Arithmetic Ability >> Geometry
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