In a circle with centre O, chords PR and QS meet at the point T, when produced, and PQ is a diameter. If ∠ROS = 42°, then the measure of ∠PTQ is:
A. 59°
B. 58°
C. 48°
D. 69°
Answer: Option D
Solution (By Examveda Team)
PSQ = 90° (Angle in semicircle)
∠TPS = $$\frac{1}{2}$$∠ROS (Angle of same arc)
∠TPS = $$\frac{1}{2}$$ × 42° = 21°
In ΔPTS
21° + ∠PTS + 90° = 180°
∠PTG = 69° Answer
This Question Belongs to Arithmetic Ability >> Geometry
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