In a DIAC the breakdown voltages are related with the following equation:
A. $${V_{B{R_1}}} = {V_{B{R_2}}} \pm 0.1{V_{B{R_2}}}$$
B. $${V_{B{R_1}}} = 2{V_{B{R_2}}}$$
C. $${V_{B{R_1}}} = \frac{{{V_{B{R_2}}}}}{2}$$
D. $${V_{B{R_1}}} = \frac{3}{2}{V_{B{R_2}}}$$
Answer: Option C
This Question Belongs to Electronics And Communications Engineering >> Power Electronics
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