In a framed structure, as shown in the below figure, the force in the member BC is

A. $$\frac{{\text{W}}}{{\sqrt 3 }}$$ (compression)
B. $$\frac{{\text{W}}}{{\sqrt 3 }}$$ (tension)
C. $$\frac{{2{\text{W}}}}{{\sqrt 3 }}$$ (compression)
D. $$\frac{{2{\text{W}}}}{{\sqrt 3 }}$$ (tension)
Answer: Option D

See here When you resolve force at point B,
then you get,
IF we get the force at away from B.
x=BC cos60=0.
y=BC sin60-w=0.
BC=2*W/3.
HERE YOU GET YOUR ANSWER TENSILE.
Can anybody explain it?