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In a framed structure, as shown in the below figure, the force in the member BC is
Engineering Mechanics mcq question image

A. $$\frac{{\text{W}}}{{\sqrt 3 }}$$ (compression)

B. $$\frac{{\text{W}}}{{\sqrt 3 }}$$ (tension)

C. $$\frac{{2{\text{W}}}}{{\sqrt 3 }}$$ (compression)

D. $$\frac{{2{\text{W}}}}{{\sqrt 3 }}$$ (tension)

Answer: Option D


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Comments ( 2 )

  1. Sourav Shrivastava
    Sourav Shrivastava :
    3 years ago

    See here When you resolve force at point B,
    then you get,

    IF we get the force at away from B.
    x=BC cos60=0.
    y=BC sin60-w=0.

    BC=2*W/3.

    HERE YOU GET YOUR ANSWER TENSILE.

  2. Munawar Sarwar
    Munawar Sarwar :
    3 years ago

    Can anybody explain it?

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If a number of forces are acting at a point, their resultant is given by

A. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2}$$

B. $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2}} $$

C. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)$$

D. $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)} $$