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In a Parson's turbine stage, blade velocity is 320 m/s at the mean radius and rotor blade exit angle is 30°. For minimum kinetic energy of the steam leaving the stage, the steam velocity at the exit of the rotor will be

A. $$\frac{{160}}{{\sqrt 3 }}{\text{m}}/{\text{s}}$$

B. $$\frac{{320}}{{\sqrt 3 }}{\text{m}}/{\text{s}}$$

C. $$\frac{{640}}{{\sqrt 3 }}{\text{m}}/{\text{s}}$$

D. $$640\,{\text{m}}/{\text{s}}$$

Answer: Option C


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Comments ( 1 )

  1. Madhavan Palmani
    Madhavan Palmani :
    4 years ago


    u/v=cos α so u has value 320; α= 30.
    320/v= cos 30.
    V=640/√3.

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