In a Parson's turbine stage, blade velocity is 320 m/s at the mean radius and rotor blade exit angle is 30°. For minimum kinetic energy of the steam leaving the stage, the steam velocity at the exit of the rotor will be
A. $$\frac{{160}}{{\sqrt 3 }}{\text{m}}/{\text{s}}$$
B. $$\frac{{320}}{{\sqrt 3 }}{\text{m}}/{\text{s}}$$
C. $$\frac{{640}}{{\sqrt 3 }}{\text{m}}/{\text{s}}$$
D. $$640\,{\text{m}}/{\text{s}}$$
Answer: Option C
This Question Belongs to Mechanical Engineering >> Steam Boilers, Engines, Nozzles And Turbines
u/v=cos α so u has value 320; α= 30.
320/v= cos 30.
V=640/√3.