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In a party every person shakes hands with every other person. If there are 105 hands shakes, find the number of person in the party.

A. 15

B. 14

C. 21

D. 25

Answer: Option A

Solution(By Examveda Team)

Let n be the number of persons in the party
Number of hands shake = 105
Total number of hands shake is given by nC2
Now,
According to the question,
$$\eqalign{ & ^n{{\text{C}}_2} = 105 \cr & {\text{or, }}\frac{{n!}}{{2! \times \left( {n - 2} \right)!}} = 105 \cr & {\text{or, }}\frac{{n \times \left( {n - 1} \right)}}{2} = 105 \cr & {\text{or, }}{n^2} - n = 210 \cr & {\text{or, }}{n^2} - n - 210 = 0 \cr & {\text{or, }}n = 15,\, - 14 \cr} $$
But, we cannot take negative value of n
So, n = 15
i.e. number of persons in the party = 15

This Question Belongs to Arithmetic Ability >> Permutation And Combination

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Comments ( 3 )

  1. Shivani Gupta
    Shivani Gupta :
    7 years ago

    Why 2????? Nc2 ????

  2. Kumar Chandan
    Kumar Chandan :
    7 years ago

    @ Ayus, Formula of Combination has been used.
    nCr = n!/[r!*(n-r)!]
    So,
    nC2 = n!/[2!*(n-2)!] as r = 2.

  3. Ayush Kulshrestha
    Ayush Kulshrestha :
    7 years ago

    how, n![2!*(n-2)!] =105 came?
    plz explain.

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