In a reversible process
A. Tds = dE + dW
B. DE - dW = Tds
C. DW - dE = Tds
D. Tds - dW + dE >0
Answer: Option A
Solution (By Examveda Team)
From second law of thermodynamics :$$\eqalign{ & TdS \geqslant \delta Q \cr & \Rightarrow TdS \geqslant dU + \delta W \cr} $$
For an irreversible process $$TdS - dU - \delta W > 0$$
And for an reversible process $$TdS - dU - \delta W = 0$$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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