In a single threaded worm and worm wheel, the number of teeth on the worm is 50. The diameter of the effort wheel is 100 mm and that of load drum is 50 mm. The velocity ratio is
A. 50
B. 100
C. 200
D. 400
Answer: Option B
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The resultant of two equal forces P making an angle $$\theta ,$$ is given by
A. $$2{\text{P}}\sin \frac{\theta }{2}$$
B. $$2{\text{P}}\cos \frac{\theta }{2}$$
C. $$2{\text{P}}\tan \frac{\theta }{2}$$
D. $$2{\text{P}}\cot \frac{\theta }{2}$$
A. Equal to
B. Less than
C. Greater than
D. None of these
If a number of forces are acting at a point, their resultant is given by
A. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2}$$
B. $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2}} $$
C. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)$$
D. $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)} $$
A. $${\text{a}} = \frac{\alpha }{{\text{r}}}$$
B. $${\text{a}} = \alpha {\text{r}}$$
C. $${\text{a}} = \frac{{\text{r}}}{\alpha }$$
D. None of these
From the given data,
No.of teeth in Worm wheel (T) = 50
Diameter of Effort wheel =100mm, so Radius (R)=100/2=50 mm
Diameter of Load Drum (d)=50mm,so radius(r) is 50/2= 25mm
Velocity Ratio for a single threaded worm and worm wheel is given by the formula
V.R = R x T / r
V.R = 50x50/25
V.R = 100
Velocity ratio for single thread is
V.R= D×T/d
V.R =TR/r
where,
T= No of teeth on worm wheel
R= radius of the effort wheel
r=radius of the worm wheel
Velocity ratio for single thread is
V.R= D×T/d
Where D is the diameter of wheel
d is the diameter of worn
V.R = 100(50/50) = 100
What is the formula for it
plz give me calculation