In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be
A. ΔQ = 0, ΔS=0
B. ΔQ = 0 , ΔS = +ve
C. ΔQ = 0, ΔS = -ve
D. ΔQ = +ve , ΔS= +ve
Answer: Option B
This Question Belongs to Chemical Engineering >> Chemical Engineering Basics
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