In a triangle PQR, PX, QY and RZ be altitudes intersecting at O. If PO = 6 cm, PX = 8 cm and QO = 4 cm, then what is the value (in cm) of QY?
A. 6.3
B. 5.8
C. 6
D. 7
Answer: Option D
Solution (By Examveda Team)

PO × OX = QO × OY = RO × OZ
6 × 2 = 4 × OY
OY = 3
∴ Then QY = QO + OY = 4 + 3 = 7 cm
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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