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In a working refrigerator, the value of COP is always
Answer & Solution
Correct Answer:
Option
D
We know COP of a refrigerator
$$\eqalign{ & = \frac{{{\text{Cooling effect}}}}{{{\text{Work taken}}}} \cr & = \frac{{{Q_L}}}{{{W_{net}}}} \cr & = \frac{{{Q_2}}}{{{Q_1} - {Q_2}}} \cr} $$
For a reversible refrigerator COP $$ = \frac{{{T_2}}}{{{T_1} - {T_2}}}$$
Since $${T_1} - {T_2} < {T_2}$$
So COP is always greater than zero.
$$\eqalign{ & = \frac{{{\text{Cooling effect}}}}{{{\text{Work taken}}}} \cr & = \frac{{{Q_L}}}{{{W_{net}}}} \cr & = \frac{{{Q_2}}}{{{Q_1} - {Q_2}}} \cr} $$
For a reversible refrigerator COP $$ = \frac{{{T_2}}}{{{T_1} - {T_2}}}$$
Since $${T_1} - {T_2} < {T_2}$$
So COP is always greater than zero.
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