In an election of 3 candidates a, b and c , a gets 50% more votes than b. a also beats c by 18000 votes .if it is known that b gets 5% more votes than c, find the number of voters on voting list ( given that 90% of voters in the list votes and no votes were illegal.

Why have you made the eqn equal to 100 when it should ve equal to 90 as the votes a b c got will be equal to peoplewho voted that is 90% of voters on list

let B get (X)% votes
therefore A=(1.5X)% (i.e.,50% more than B)
C=(X-5)% (B gets 5% more than C)
total votes A+B+C=1.5X+X+(X-5)=100
on solving we get 3.5X=105...i.e., X=30
X is nothing but B
therefore
A=(1.5*30=45)
B=30
C=25
Now, if @ 45 votes A beat C by 20
then if A beat C by 18000 votes (cross-multiplication) we will have vote for A
A=40500
now for B and C
if @ A=45 real value of A is 40500 the for B(@30) we have real value =27000 and similar for C we get C=22500 (Cross multiplication)
now adding A+B+C=40500+27000+22500=90,000( given that 90% of voters in the list votes ) therefore total voters will be 1,00,000

is answer 81000?

No

Explain in detail rajput sir

D