In an interchangeable assembly, shafts of size 25.000 -0.0100⁺⁰∙⁰⁴⁰ mm mate with holes of size 25.000 -0.010⁺⁰∙⁰²⁰ mm. The maximum possible clearance in the assembly will be

Define the shaft and hole dimensions:
Shaft Size: 25.000 -0.010⁺⁰∙⁰⁴⁰ mm
Hole Size: 25.000 -0.010⁺⁰∙⁰²⁰ mm

Calculate the maximum and minimum shaft dimensions:
Maximum Shaft: 25.000 + 0.040 = 25.040 mm
Minimum Shaft: 25.000 - 0.010 = 24.990 mm

Calculate the maximum and minimum hole dimensions:
Maximum Hole: 25.000 + 0.020 = 25.020 mm
Minimum Hole: 25.000 - 0.010 = 24.990 mm

Calculate the maximum clearance:
Maximum Clearance = Maximum Hole - Minimum Shaft
Maximum Clearance = 25.020 mm - 24.990 mm = 0.030 mm

Convert to microns:
0.030 mm = 30 microns

The correct answer is: 60 microns
Max shaft = 24.99 mm
Min shaft = 24.96 mm
Max Hole = 25.02 mm
Min Hole 25.01 mm

Min. clearance = Min. Hole - Max Shaft = 20 microns
Max. clearance = Max Hole - Minimum shaft = 60 microns

From the above que clearance is only 20microns how is it possible for 30microns its the wrong ans know

Maximum possible clearance = Hole max size - Shaft min size = 25.02 -24.99 = 0.03 (30 microns)
Here 25.02 = 25 + 0.02 (max tolerance value) &
24.99 = 25 - 0.01 (min tolerance value)

25.02-24.99= .03

This is interference fit. Max upper limit - Min lower limit gives clearance. So, 0.04-0.01 = 0.03 mm = 30 microns.

Please show the procedure

nice question.