Examveda
Examveda

In an interchangeable assembly, shafts of size 25.000 -0.0100⁺⁰∙⁰⁴⁰ mm mate with holes of size 25.000 -0.010⁺⁰∙⁰²⁰ mm. The maximum possible clearance in the assembly will be

A. 10 microns

B. 20 microns

C. 30 microns

D. 60 microns

Answer: Option C


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Comments ( 6 )

  1. MOHAN BABU
    MOHAN BABU :
    3 years ago

    From the above que clearance is only 20microns how is it possible for 30microns its the wrong ans know

  2. V UMA
    V UMA :
    4 years ago

    Maximum possible clearance = Hole max size - Shaft min size = 25.02 -24.99 = 0.03 (30 microns)
    Here 25.02 = 25 + 0.02 (max tolerance value) &
    24.99 = 25 - 0.01 (min tolerance value)

  3. Ashok Mehata
    Ashok Mehata :
    4 years ago

    25.02-24.99= .03

  4. Johnson Ebenezer
    Johnson Ebenezer :
    4 years ago

    This is interference fit. Max upper limit - Min lower limit gives clearance. So, 0.04-0.01 = 0.03 mm = 30 microns.

  5. Managobinda Sahoo
    Managobinda Sahoo :
    4 years ago

    Please show the procedure

  6. Danish Siddiqui
    Danish Siddiqui :
    5 years ago

    nice question.

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