In an irreversible process

A. Tds = dE - dW = 0

B. DE - dW - Tds = 0

C. Tds - dE + dW< 0

D. Tds - dT + dW< 0

Answer: Option C

Solution(By Examveda Team)

From second law of thermodynamics :
$$\eqalign{ & TdS \geqslant \delta Q \cr & \Rightarrow TdS \geqslant dU + \delta W \cr} $$
For an irreversible process $$TdS - dU - \delta W > 0$$
And for an reversible process $$TdS - dU - \delta W = 0$$