In an isosceles triangle ABC with AB = AC and AD is perpendicular to BC. If AD = 6 cm and the perimeter of ΔABC is 36 cm, then the area of ΔABC is:
A. 45 cm2
B. 48 cm2
C. 54 cm2
D. 64 cm2
Answer: Option B
Solution (By Examveda Team)
Perimeter of triangle ABC = 36 cm
By Pythagorean triplets 6, 8, 10
Now,
a = 8 cm
x = 10 cm
Area of triangle ABC = $$\frac{1}{2}$$ × 16 × 6 = 48 cm2
This Question Belongs to Arithmetic Ability >> Geometry
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