In an orthogonal cutting, the depth of cut is halved and the feed rate is double. If the chip thickness ratio is unaffected with the changed cutting conditions, the actual chip thickness will be

Chip thickness ratio (r)=t/tc
Now it's given feed that means the question is of orthogonal turning
For orthogonal turning t=f
Where f is feed
Now it's given that feed is double nd we have to maintain constant chip thickness ratio therefore
r=f/tc--------1
Feed is double nd r is constant
r=2f/tc'---------2
From 1 and 2
f/tc=2f/tc'
Therefore tc'=2tc
Therefore answer is chip thickness will be DOUBLED

we know that: r= t/tc i,e t= uncut chip thickness or depth of cut, tc= actual chip thickness, r= cutting ratio
for same r now we have = t/0.5tc = 2t/tc as 1/0.5 or 1/(1/2)= 2/1. thus actual chip thickness is doubled.

It should be halved

How?