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Permutation and Combination
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In how many ways 2 students can be chosen from the class of 20 students?

Answer & Solution
Correct Answer: Option A
Number of ways
$$\eqalign{ & { = ^{20}}{{\text{C}}_2} \cr & = \frac{{20!}}{{2! \times 18!}} \cr & = 20 \times \frac{{19}}{2} \cr & = 190 \cr} $$
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