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In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{Required number of ways}} \cr
& = {{}^7{C_5} \times {}^3{C_2}} \cr
& = {{}^7{C_2} \times {}^3{C_1}} \cr
& = {\frac{{7 \times 6}}{{2 \times 1}} \times 3} \cr
& = 63 \cr} $$
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