In how many ways can seven friends be seated in a row having 35 seats, such that no two friends occupy adjacent seats?
A. 29P7
B. 29C7
C. 28P7
D. 28C7
Answer: Option A
Solution(By Examveda Team)
First let us consider the 28 unoccupied seats. They create 29 slots - one on the left of each seat and one on the right of the last one. We can place the 7 friends in any of these 29 slots i.e. 29P7 ways.This Question Belongs to Arithmetic Ability >> Permutation And Combination
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Comments ( 2 )
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I believe the better explanation is there should be a gap between each friend......
which means a min of 6 empty seats between them if they are sitting closest to each other....like X_X_X_X (X=occupied seat, _ = empty seat )......
This leaves 29 available seats. 7 friends can occupy them 29P7 ways
hi, Sir/ madam,
In how many ways can seven friends be seated in a row having 40 seats, such that no to friends occupy adjacent seats?
this is a solve answer.
Help me.