In one’s complement 8 bit representation 11111111 represents
A. +0
B. -0
C. +1
D. -1
Answer: Option B
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Related Questions on Microprocessors and Microcontrollers
A. Circuit A has more gates than circuit B
B. Circuit B has more gates than circuit A
C. Circuit A has the same number of gates as circuit B
D. None of the above
For the number A[15:0] = 0110110010001111, A[14:13] is ______ A[3:2].
A. Less than
B. Greater than
C. The same as
D. Cannot be determined
How it will -0 please explain in details
Bcz in 1 complement,
-0, +0 both exist -2^(n-1)-1, +2^(n-1)-1
If n=6 then the range is -32..-0+0.. +32
And similarly for signed number.
But in case of 2 compliment , only 0 is present
-2^(n-1 ) to +2^(n-1) -1
If n=6
-32... 0...31
how it will be -0 ?explain
How it will be -0? Can u give me an explanation about it. So that I can clarify my doubt. Actually, I thought that answer is option A.
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