In orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool, the cutting velocity is 90 m/min. The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm. If the orthogonal rake angle is zero and the principle cutting edge angle is 90°, the shear angle in degree is
A. 20.56
B. 26.56
C. 30.56
D. 36.56
Answer: Option B
This Question Belongs to Mechanical Engineering >> Manufacturing And Production Technology
Join The Discussion
Comments ( 1 )
Related Questions on Manufacturing and Production Technology
The carbide tools operating at very low cutting speeds (below 30 m/min)
A. Reduces tool life
B. Increases tool life
C. Have no effect on tool life
D. Spoils the work piece
The type of reamer used for reaming operation in a blind hole, is
A. Straight fluted reamer
B. Left hand spiral fluted reamer
C. Right hand spiral fluted reamer
D. Any one of these
High speed steel tools retain their hardness up to a temperature of
A. 250°C
B. 350°C
C. 500°C
D. 900°C
Option B is correct.
Ans: Shear angle is given as tan@= rcos@ ÷ 1-rsin@@
Where, r= t÷tc,. Tc=0.48
t , fsin(90)= 0.24×1= 0.24
Hence ,. r= 0.24÷0.48= 0.5
given as tan@= rcos@ ÷ 1-rsin@
Put value r , we get @=26.56