In Sabarmati Express, there are as many wagons as the number of seats in each wagon and not more than one passenger can have the same berth (seat). If the middlemost compartment carrying 25 passengers is filled with 71.428% of its capacity, then find the maximum no. of passengers in the train that can be accommodated if it has minimum 20% seats always vacant.

Solution (By Examveda Team)

Given,

25 passengers are equal to 71.428% of total capacity of wagon.

Means, 71.428% passengers = 25.

1% passengers = 25/71.428

Hence, 100% passengers = (25*100)/71.428 = 35 passengers.

Capacity of one wagon = 35.

So, number of wagon = 35.

Total capacity of the train = 35 *35 = 1225.

Also, given 20% seat remains vacant.

Thus, the number of passengers in the train,

= 1225 - 20% of 1225 = 1225 - 245 = 980.