In the deuterium + tritium (d + t) fusion more energy is released as compared to deuterium + deuterium (d + d) fusion because
A. tritium is radioactive
B. more nucleons participate in fusion
C. the Coulomb barrier is lower for the d + t system than d + d system
D. the reaction product 4He is more tightly bound
Answer: Option A
A. Thorium series
B. Neptunium series
C. Uranium series
D. Actinium series
A. 10-10 eV
B. 10-9 eV
C. 10-6 eV
D. 10-4 eV
A. The process is allowed because ΔS = 0
B. The process is allowed because $$\Delta {I_3} = 0$$
C. The process is not allowed because ΔS ≠ 1 and $$\Delta {I_3} \ne 0$$
D. The process is not allowed because the Baryon number is violated
A. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^3};\,J = \frac{3}{2}$$
B. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^1};\,J = \frac{3}{2}$$
C. $${\left( {{}^1{s_{1/2}}} \right)^1}{\left( {{}^1{p_{3/2}}} \right)^4};\,J = \frac{1}{2}$$
D. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^2}{\left( {{}^1{p_{1/2}}} \right)^1};\,J = \frac{1}{2}$$
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