In the following figure if angles ABC = 95 FED =...

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In the following figure, if angles ∠ABC = 95°, ∠FED = 115° (not to scale). Then the angle ∠APC is equal to:

A. 120°

B. 150°

C. 135°

D. 155°

Answer: Option B

Solution (By Examveda Team)

(External angle of ΔAFP)
∠ABC = 95°, ∠FED = 115°
In, $$\square $$ FABC,
∠AFC = 180° - 95° = 85°
In $$\square $$ FEDA,
∠FAD = 180° - 115° = 65°
So, ∠APC = 85° + 65° = 150°

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