In the following figure (not to scale), at the centre O, if the chord AB students double the angle that is subtended by chord CD and the angle ∠AEB = 2∠AOB, then ∠COD is equal to:

A. 30°
B. 45°
C. 60°
D. 75°
Answer: Option A
Solution (By Examveda Team)

$$\eqalign{ & 4x + 2x = {180^ \circ } \cr & 6x = {180^ \circ } \cr & \angle COD = x = \frac{{{{180}^ \circ }}}{6} = {30^ \circ } \cr} $$
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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