In the given figure, ABCDEF is a regular hexagon of side 12 cm P, Q and R are the mid points of the sides AB, CD and EF respectively. What is the area (in cm²) of triangle PQR?

Solution (By Examveda Team)

So, If
OF = OE = ED
So, FC = 24 cm
So, RQ $$ = \frac{{{\text{FC}} + {\text{ED}}}}{2} = \frac{{36}}{2}$$
RQ = 18 cm
Area of $$\Delta {\text{PQR}} = \frac{{\sqrt 3 }}{4} \times 18 \times 18 = 81\sqrt 3 {\text{ c}}{{\text{m}}^2}$$