In the given figure, AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF. If the angle at C is 34°, the angle ∠ADB is:

Solution (By Examveda Team)

$$\eqalign{ & \angle {\text{D}} = \frac{{\angle {\text{C}}}}{2}\left( {{\text{by angle bisector theorem}}} \right) \cr & \angle {\text{D}} = \frac{{34}}{2} \cr & \angle {\text{D}} = {17^ \circ } \cr} $$