In the given figure, diameter AB and chord CD of a circle meet at P. PT is a tangent to the circle at T. If CD = 7.8 cm, PD = 5 cm, PB = 4 cm, find AB.
A. 12 cm
B. 11 cm
C. 8 cm
D. 10 cm
Answer: Option A
Solution (By Examveda Team)
⇒ PT2 = PD × PC . . . . . . (1)
PT2 = PB × PA . . . . . . (2)
⇒ PD × PC = PB × PA
5 × 12.8 = 4 × (4 + AB)
5 × 3.2 = (4 + AB)
16 = 4 + AB
AB = 12 Answer
This Question Belongs to Arithmetic Ability >> Geometry
Join The Discussion