In the given figure if AC DE are parallel and CAB...

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In the given figure, if AC, DE are parallel and ∠CAB = 38°, then the value of ∠ABC + 5∠CBD is:

A. 158°

B. 178°

C. 218°

D. 196°

Answer: Option C

Solution (By Examveda Team)

If AC || BD,
2a + b + a = 180° . . . . . . (1)
2a = 38°
a = 19°
From equation (1)
2 × 19° + b + 19° = 180°
b = 123°
Now,
∠ABC + 5∠CBD
= 123° + 5 × 19°
= 218°

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