In the given figure, O is the centre of the circle. If ∠BAO = 30° and ∠BCO = 50°, then ∠AOC is equal to:

A. 160°
B. 60°
C. 40°
D. 80°
Answer: Option A
Solution (By Examveda Team)

Let, Angle ABC = x
Then, Angle AOC = 2x
In Quadrilateral ABCO,
30° + 50° + x + 360° - 2x = 360°
⇒ x = 80°
So, 2x = 160°
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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