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In the given figure PQ is a diameter of the semicircle...

This question belongs to Arithmetic Ability Geometry
Geometry
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In the given figure, PQ is a diameter of the semicircle PABQ and O is its center. ∠AOB = 64°. BP cuts AQ at X. What is the value (in degrees) of ∠AXP?
Geometry mcq question image

Answer & Solution
Correct Answer: Option C
Geometry mcq question image
∠AOB = 64°
Then,
∠BPA = 32°
∠PAQ = 90°
[∴ PQ is a diameter]
So, ∠PXA = 90 - 32 = 58°
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