In the given figure, PT is a common tangent to three circles at points A, B and C respectively. The radius of the small, medium and large circles is 4 cm, 6 cm and 9 cm. O1, O2 and O3 are the centre of the three circles what is the value (in cm) of PC?

A. 18√6
B. 9√6
C. 24√6
D. 15√6
Answer: Option A
Solution (By Examveda Team)

ΔPO1A is similar to ΔPO2B
AO1 : BO2 = 2 : 3
O1O2 = 10 = 3 - 2 = 1 unit
1 unit → 10
PO2 = 3 units → 30
ΔPO3C is similar to ΔPO2B.
BO2 : CO3 = 2 : 3
2 units → 30
1 unit → 15
PO3 = 45
CO3 = 9
$$\eqalign{ & {\text{PC}} = \sqrt {{{45}^2} - {9^2}} \cr & = \sqrt {2025 - 81} \cr & = \sqrt {1944} \cr & = 18\sqrt 6 \cr} $$
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