In ΔPQR, ∠Q = 84° and ∠R = 48°, PS ⊥ QR at S and the bisector of ∠P meets QR at T. What is the measure of ∠SPT ?
A. 12°
B. 24°
C. 21°
D. 18°
Answer: Option D
Solution (By Examveda Team)
∠QPR = 180° - (84° + 48°) = 48°
∠QPT = $$\frac{{{{48}^ \circ }}}{2}$$ = 24°
∠QPS = 6°
∠SPT + ∠SPQ = 24°
∠SPT + 6° = 24°
∠SPT = 18°
This Question Belongs to Arithmetic Ability >> Geometry
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