ExamVeda
Login
Home

In triangle PQR C is the centroid PQ = 30 cm...

This question belongs to Arithmetic Ability Geometry
Geometry
?

In triangle PQR, C is the centroid. PQ = 30 cm, QR = 36 cm and PR = 50 cm. If D is the midpoint of QR, then what is the length (in cm) of CD ?

Answer & Solution
Correct Answer: Option A
Geometry mcq question image
(PQ)2 + (PR)2 = 2(QD2 + PD2)
(30)2 + (50)2 = 2[(18)2 + PD2]
900 + 2500 = 2[324 + PD2]
3400 = 2[324 + PD2]
1700 = 324 + PD2
PD2 = 1376
PD = $$4\sqrt {86} $$
CD = $$\frac{1}{3}$$PD
CD = $$\frac{{4\sqrt {86} }}{3}$$
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.
Keep Learning

Related Questions on Geometry

ln a square ABCD, diagonals AC and BD interest at O. The angle bisector of ∠CAB meets BD and BC at F and G, respectively. OF : CG is equal to:
A. 1 : 2 B. 1 : 3 C. 1 : √3 D. 1 : √2
In the given figure, PQR is a triangle and quadrilateral ABCD is inscribed in it, QD = 2 cm, QC = 5 cm, CR = 3 cm, BR = 4 cm, PB = 6 cm, PA = 5 cm and AD = 3 cm. What is the area (in cm2) of the quadrilateral ABCD?
Geometry mcq question image
A. $$\frac{{23\sqrt {21} }}{4}$$ B. $$\frac{{15\sqrt {21} }}{4}$$ C. $$\frac{{17\sqrt {21} }}{5}$$ D. $$\frac{{23\sqrt {21} }}{5}$$
In ΔABC, AC = BC and ∠ABC = 50°, the side BC is produced to D so that BC = CD then the value of ∠BAD?
A. 80° B. 40° C. 90° D. 50°
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
Geometry mcq question image
A. 30° B. 40° C. 20° D. 70°
More Related Questions on Geometry